Base | Representation |
---|---|
bin | 11101011011111011111… |
… | …11000111011101101011 |
3 | 10120200200100220000022101 |
4 | 32231331333013131223 |
5 | 113032402314342303 |
6 | 2052351152434231 |
7 | 133034126516143 |
oct | 16557577073553 |
9 | 3520610800271 |
10 | 1011431012203 |
11 | 35aa44490617 |
12 | 144032248977 |
13 | 744ba5a23a1 |
14 | 36d4c671923 |
15 | 1b49a092d1d |
hex | eb7dfc776b |
1011431012203 has 2 divisors, whose sum is σ = 1011431012204. Its totient is φ = 1011431012202.
The previous prime is 1011431012201. The next prime is 1011431012233. The reversal of 1011431012203 is 3022101341101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1011431012203 - 21 = 1011431012201 is a prime.
Together with 1011431012201, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1011431012201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505715506101 + 505715506102.
It is an arithmetic number, because the mean of its divisors is an integer number (505715506102).
Almost surely, 21011431012203 is an apocalyptic number.
1011431012203 is a deficient number, since it is larger than the sum of its proper divisors (1).
1011431012203 is an equidigital number, since it uses as much as digits as its factorization.
1011431012203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1011431012203 its reverse (3022101341101), we get a palindrome (4033532353304).
The spelling of 1011431012203 in words is "one trillion, eleven billion, four hundred thirty-one million, twelve thousand, two hundred three".
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