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10114325400553 = 11919484127323
BaseRepresentation
bin1001001100101110110011…
…0001011100101111101001
31022210220211201122100021221
42103023230301130233221
52311203114300304203
633302242411102041
72062510261252063
oct223135461345751
938726751570257
1010114325400553
11324a509010630
121174283141921
13584a137c922a
1426d77096c733
1512816bb3aabd
hex932ecc5cbe9

10114325400553 has 4 divisors (see below), whose sum is σ = 11033809527888. Its totient is φ = 9194841273220.

The previous prime is 10114325400527. The next prime is 10114325400581. The reversal of 10114325400553 is 35500452341101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10114325400553 - 233 = 10105735465961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10114325400653) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 459742063651 + ... + 459742063672.

It is an arithmetic number, because the mean of its divisors is an integer number (2758452381972).

Almost surely, 210114325400553 is an apocalyptic number.

It is an amenable number.

10114325400553 is a deficient number, since it is larger than the sum of its proper divisors (919484127335).

10114325400553 is an equidigital number, since it uses as much as digits as its factorization.

10114325400553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 919484127334.

The product of its (nonzero) digits is 36000, while the sum is 34.

Adding to 10114325400553 its reverse (35500452341101), we get a palindrome (45614777741654).

The spelling of 10114325400553 in words is "ten trillion, one hundred fourteen billion, three hundred twenty-five million, four hundred thousand, five hundred fifty-three".

Divisors: 1 11 919484127323 10114325400553