Base | Representation |
---|---|
bin | 1001001100101110110100… |
… | …1111101111010111110101 |
3 | 1022210220212021120202202222 |
4 | 2103023231033233113311 |
5 | 2311203123313404143 |
6 | 33302243253212125 |
7 | 2062510415613425 |
oct | 223135517572765 |
9 | 38726767522688 |
10 | 10114333341173 |
11 | 324a512544526 |
12 | 1174285931045 |
13 | 584a15349619 |
14 | 26d771a38485 |
15 | 12816c6a8768 |
hex | 932ed3ef5f5 |
10114333341173 has 2 divisors, whose sum is σ = 10114333341174. Its totient is φ = 10114333341172.
The previous prime is 10114333341131. The next prime is 10114333341181. The reversal of 10114333341173 is 37114333341101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7420818877924 + 2693514463249 = 2724118^2 + 1641193^2 .
It is a cyclic number.
It is not a de Polignac number, because 10114333341173 - 222 = 10114329146869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10114333341103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057166670586 + 5057166670587.
It is an arithmetic number, because the mean of its divisors is an integer number (5057166670587).
Almost surely, 210114333341173 is an apocalyptic number.
It is an amenable number.
10114333341173 is a deficient number, since it is larger than the sum of its proper divisors (1).
10114333341173 is an equidigital number, since it uses as much as digits as its factorization.
10114333341173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27216, while the sum is 35.
Adding to 10114333341173 its reverse (37114333341101), we get a palindrome (47228666682274).
The spelling of 10114333341173 in words is "ten trillion, one hundred fourteen billion, three hundred thirty-three million, three hundred forty-one thousand, one hundred seventy-three".
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