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1011440320097 is a prime number
BaseRepresentation
bin11101011011111101000…
…10100111111001100001
310120200201000101220100012
432231332202213321201
5113032412210220342
62052352124134305
7133034301603644
oct16557642477141
93520630356305
101011440320097
1135aa49768799
12144035397395
13744bc4b0c0c
1436d4d9b5a5b
151b49acd0b82
hexeb7e8a7e61

1011440320097 has 2 divisors, whose sum is σ = 1011440320098. Its totient is φ = 1011440320096.

The previous prime is 1011440320091. The next prime is 1011440320129. The reversal of 1011440320097 is 7900230441101.

It is an a-pointer prime, because the next prime (1011440320129) can be obtained adding 1011440320097 to its sum of digits (32).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 794895281761 + 216545038336 = 891569^2 + 465344^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1011440320097 is a prime.

It is a super-2 number, since 2×10114403200972 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1011440320091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505720160048 + 505720160049.

It is an arithmetic number, because the mean of its divisors is an integer number (505720160049).

Almost surely, 21011440320097 is an apocalyptic number.

It is an amenable number.

1011440320097 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011440320097 is an equidigital number, since it uses as much as digits as its factorization.

1011440320097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 32.

Adding to 1011440320097 its reverse (7900230441101), we get a palindrome (8911670761198).

The spelling of 1011440320097 in words is "one trillion, eleven billion, four hundred forty million, three hundred twenty thousand, ninety-seven".