Base | Representation |
---|---|
bin | 1001001100101111000101… |
… | …1110100101100101110111 |
3 | 1022210221001020011222210020 |
4 | 2103023301132211211313 |
5 | 2311203300002422020 |
6 | 33302254311100223 |
7 | 2062512240246342 |
oct | 223136136454567 |
9 | 38727036158706 |
10 | 10114404342135 |
11 | 324a549629605 |
12 | 11742a5671673 |
13 | 584a26c78922 |
14 | 26d77b23b459 |
15 | 128173a30c40 |
hex | 932f17a5977 |
10114404342135 has 32 divisors (see below), whose sum is σ = 16426330744320. Its totient is φ = 5313396547200.
The previous prime is 10114404342043. The next prime is 10114404342143. The reversal of 10114404342135 is 53124340441101.
It is not a de Polignac number, because 10114404342135 - 211 = 10114404340087 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10114404342096 and 10114404342105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3303561 + ... + 5580530.
It is an arithmetic number, because the mean of its divisors is an integer number (513322835760).
Almost surely, 210114404342135 is an apocalyptic number.
10114404342135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
10114404342135 is a deficient number, since it is larger than the sum of its proper divisors (6311926402185).
10114404342135 is a wasteful number, since it uses less digits than its factorization.
10114404342135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8885239.
The product of its (nonzero) digits is 23040, while the sum is 33.
Adding to 10114404342135 its reverse (53124340441101), we get a palindrome (63238744783236).
The spelling of 10114404342135 in words is "ten trillion, one hundred fourteen billion, four hundred four million, three hundred forty-two thousand, one hundred thirty-five".
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