101144131222 has 4 divisors (see below), whose sum is σ = 151716196836. Its totient is φ = 50572065610.

The previous prime is 101144131217. The next prime is 101144131273. The reversal of 101144131222 is 222131441101.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 101144131193 and 101144131202.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25286032804 + ... + 25286032807.

It is an arithmetic number, because the mean of its divisors is an integer number (37929049209).

Almost surely, 2^101144131222 is an apocalyptic number.

101144131222 is a deficient number, since it is larger than the sum of its proper divisors (50572065614).

101144131222 is an equidigital number, since it uses as much as digits as its factorization.

101144131222 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50572065613.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 101144131222 its reverse (222131441101), we get a palindrome (323275572323).

The spelling of 101144131222 in words is "one hundred one billion, one hundred forty-four million, one hundred thirty-one thousand, two hundred twenty-two".