Base | Representation |
---|---|
bin | 1001001100101111100010… |
… | …1011011100101100000011 |
3 | 1022210221100122111212120122 |
4 | 2103023320223130230003 |
5 | 2311204021414412201 |
6 | 33302314304330455 |
7 | 2062515235161563 |
oct | 223137053345403 |
9 | 38727318455518 |
10 | 10114525154051 |
11 | 324a60084536a |
12 | 117431a013a2b |
13 | 584a45cc8276 |
14 | 26d78d2c8da3 |
15 | 12817e446e1b |
hex | 932f8adcb03 |
10114525154051 has 4 divisors (see below), whose sum is σ = 10114553675832. Its totient is φ = 10114496632272.
The previous prime is 10114525154047. The next prime is 10114525154053. The reversal of 10114525154051 is 15045152541101.
10114525154051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10114525154051 - 22 = 10114525154047 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10114525154053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13722170 + ... + 14440463.
It is an arithmetic number, because the mean of its divisors is an integer number (2528638418958).
Almost surely, 210114525154051 is an apocalyptic number.
10114525154051 is a deficient number, since it is larger than the sum of its proper divisors (28521781).
10114525154051 is an equidigital number, since it uses as much as digits as its factorization.
10114525154051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28521780.
The product of its (nonzero) digits is 20000, while the sum is 35.
Adding to 10114525154051 its reverse (15045152541101), we get a palindrome (25159677695152).
The spelling of 10114525154051 in words is "ten trillion, one hundred fourteen billion, five hundred twenty-five million, one hundred fifty-four thousand, fifty-one".
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