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10114525154053 is a prime number
BaseRepresentation
bin1001001100101111100010…
…1011011100101100000101
31022210221100122111212120201
42103023320223130230011
52311204021414412203
633302314304330501
72062515235161565
oct223137053345405
938727318455521
1010114525154053
11324a600845371
12117431a013a31
13584a45cc8278
1426d78d2c8da5
1512817e446e1d
hex932f8adcb05

10114525154053 has 2 divisors, whose sum is σ = 10114525154054. Its totient is φ = 10114525154052.

The previous prime is 10114525154047. The next prime is 10114525154057. The reversal of 10114525154053 is 35045152541101.

10114525154053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10114136354529 + 388799524 = 3180273^2 + 19718^2 .

It is a cyclic number.

It is not a de Polignac number, because 10114525154053 - 217 = 10114525022981 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10114525154057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5057262577026 + 5057262577027.

It is an arithmetic number, because the mean of its divisors is an integer number (5057262577027).

Almost surely, 210114525154053 is an apocalyptic number.

It is an amenable number.

10114525154053 is a deficient number, since it is larger than the sum of its proper divisors (1).

10114525154053 is an equidigital number, since it uses as much as digits as its factorization.

10114525154053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60000, while the sum is 37.

Adding to 10114525154053 its reverse (35045152541101), we get a palindrome (45159677695154).

The spelling of 10114525154053 in words is "ten trillion, one hundred fourteen billion, five hundred twenty-five million, one hundred fifty-four thousand, fifty-three".