Base | Representation |
---|---|
bin | 10110111111111101010000… |
… | …010100110111011010001011 |
3 | 111021011001022022221100101211 |
4 | 112333331100110313122023 |
5 | 101224234021320411321 |
6 | 555044351000553551 |
7 | 30206666614230301 |
oct | 2677752024673213 |
9 | 437131268840354 |
10 | 101152122435211 |
11 | 2a2594130a2201 |
12 | b417b611828b7 |
13 | 44597b1605753 |
14 | 1ad9b08856271 |
15 | ba62eb1100e1 |
hex | 5bff5053768b |
101152122435211 has 2 divisors, whose sum is σ = 101152122435212. Its totient is φ = 101152122435210.
The previous prime is 101152122435197. The next prime is 101152122435223. The reversal of 101152122435211 is 112534221251101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101152122435211 - 211 = 101152122433163 is a prime.
It is a super-2 number, since 2×1011521224352112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (101152123435211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50576061217605 + 50576061217606.
It is an arithmetic number, because the mean of its divisors is an integer number (50576061217606).
Almost surely, 2101152122435211 is an apocalyptic number.
101152122435211 is a deficient number, since it is larger than the sum of its proper divisors (1).
101152122435211 is an equidigital number, since it uses as much as digits as its factorization.
101152122435211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4800, while the sum is 31.
Adding to 101152122435211 its reverse (112534221251101), we get a palindrome (213686343686312).
The spelling of 101152122435211 in words is "one hundred one trillion, one hundred fifty-two billion, one hundred twenty-two million, four hundred thirty-five thousand, two hundred eleven".
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