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101155134343 = 144077021249
BaseRepresentation
bin101111000110101010…
…0001101101110000111
3100200002200020020200011
41132031110031232013
53124131203244333
6114245305331051
710210501312054
oct1361524155607
9320080206604
10101155134343
113999948868a
1217730796a87
139700c257a3
144c7863202b
1529708619cd
hex178d50db87

101155134343 has 4 divisors (see below), whose sum is σ = 101162170000. Its totient is φ = 101148098688.

The previous prime is 101155134293. The next prime is 101155134361. The reversal of 101155134343 is 343431551101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101155134343 is a prime.

It is a super-2 number, since 2×1011551343432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101155134043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3496218 + ... + 3525031.

It is an arithmetic number, because the mean of its divisors is an integer number (25290542500).

Almost surely, 2101155134343 is an apocalyptic number.

101155134343 is a deficient number, since it is larger than the sum of its proper divisors (7035657).

101155134343 is an equidigital number, since it uses as much as digits as its factorization.

101155134343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7035656.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 101155134343 its reverse (343431551101), we get a palindrome (444586685444).

The spelling of 101155134343 in words is "one hundred one billion, one hundred fifty-five million, one hundred thirty-four thousand, three hundred forty-three".

Divisors: 1 14407 7021249 101155134343