10115524113 has 4 divisors (see below), whose sum is σ = 13487365488. Its totient is φ = 6743682740.

The previous prime is 10115524109. The next prime is 10115524117. The reversal of 10115524113 is 31142551101.

10115524113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31142551101 = 3 ⋅10380850367.

It is an interprime number because it is at equal distance from previous prime (10115524109) and next prime (10115524117).

It is a cyclic number.

It is not a de Polignac number, because 10115524113 - 2² = 10115524109 is a prime.

It is not an unprimeable number, because it can be changed into a prime (10115524117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685920683 + ... + 1685920688.

It is an arithmetic number, because the mean of its divisors is an integer number (3371841372).

Almost surely, 2^10115524113 is an apocalyptic number.

It is an amenable number.

10115524113 is a deficient number, since it is larger than the sum of its proper divisors (3371841375).

10115524113 is an equidigital number, since it uses as much as digits as its factorization.

10115524113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3371841374.

The product of its (nonzero) digits is 600, while the sum is 24.

The spelling of 10115524113 in words is "ten billion, one hundred fifteen million, five hundred twenty-four thousand, one hundred thirteen".