101200040113 has 4 divisors (see below), whose sum is σ = 104464557568. Its totient is φ = 97935522660.

The previous prime is 101200040093. The next prime is 101200040131. The reversal of 101200040113 is 311040002101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101200040113 - 2⁹ = 101200039601 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101200040093 and 101200040102.

It is not an unprimeable number, because it can be changed into a prime (101200049113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1632258681 + ... + 1632258742.

It is an arithmetic number, because the mean of its divisors is an integer number (26116139392).

Almost surely, 2^101200040113 is an apocalyptic number.

It is an amenable number.

101200040113 is a deficient number, since it is larger than the sum of its proper divisors (3264517455).

101200040113 is an equidigital number, since it uses as much as digits as its factorization.

101200040113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3264517454.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 101200040113 its reverse (311040002101), we get a palindrome (412240042214).

The spelling of 101200040113 in words is "one hundred one billion, two hundred million, forty thousand, one hundred thirteen".