101200101111211 has 4 divisors (see below), whose sum is σ = 101375491235032. Its totient is φ = 101024710987392.

The previous prime is 101200101111209. The next prime is 101200101111251. The reversal of 101200101111211 is 112111101002101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101200101111211 - 2¹ = 101200101111209 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101200101111191 and 101200101111200.

It is not an unprimeable number, because it can be changed into a prime (101200101111251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87695061045 + ... + 87695062198.

It is an arithmetic number, because the mean of its divisors is an integer number (25343872808758).

Almost surely, 2^{101200101111211} is an apocalyptic number.

101200101111211 is a deficient number, since it is larger than the sum of its proper divisors (175390123821).

101200101111211 is an equidigital number, since it uses as much as digits as its factorization.

101200101111211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 175390123820.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 101200101111211 its reverse (112111101002101), we get a palindrome (213311202113312).

The spelling of 101200101111211 in words is "one hundred one trillion, two hundred billion, one hundred one million, one hundred eleven thousand, two hundred eleven".