Base | Representation |
---|---|
bin | 111100010100100… |
… | …000111000110111 |
3 | 2121112021110111021 |
4 | 330110200320313 |
5 | 4033033314201 |
6 | 244230522011 |
7 | 34035643036 |
oct | 7424407067 |
9 | 2545243437 |
10 | 1012010551 |
11 | 47a287562 |
12 | 242b06307 |
13 | 131883c16 |
14 | 9859671d |
15 | 5dca4ea1 |
hex | 3c520e37 |
1012010551 has 4 divisors (see below), whose sum is σ = 1012421592. Its totient is φ = 1011599512.
The previous prime is 1012010543. The next prime is 1012010581. The reversal of 1012010551 is 1550102101.
1012010551 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1550102101 = 31607 ⋅49043.
It is a cyclic number.
It is not a de Polignac number, because 1012010551 - 23 = 1012010543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1012010581) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 201805 + ... + 206758.
It is an arithmetic number, because the mean of its divisors is an integer number (253105398).
Almost surely, 21012010551 is an apocalyptic number.
1012010551 is a deficient number, since it is larger than the sum of its proper divisors (411041).
1012010551 is an equidigital number, since it uses as much as digits as its factorization.
1012010551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 411040.
The product of its (nonzero) digits is 50, while the sum is 16.
The square root of 1012010551 is about 31812.1132746632. The cubic root of 1012010551 is about 1003.9875949510.
Adding to 1012010551 its reverse (1550102101), we get a palindrome (2562112652).
The spelling of 1012010551 in words is "one billion, twelve million, ten thousand, five hundred fifty-one".
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