Base | Representation |
---|---|
bin | 10111000000101010111101… |
… | …101001011111101110000011 |
3 | 111021022201222201021220220011 |
4 | 113000222331221133232003 |
5 | 101231040030001400003 |
6 | 555123105013125351 |
7 | 30213355051652152 |
oct | 2700527551375603 |
9 | 437281881256804 |
10 | 101201201200003 |
11 | 2a278208849643 |
12 | b425579629857 |
13 | 4461303555388 |
14 | 1adc242a9d599 |
15 | ba771eb8146d |
hex | 5c0abda5fb83 |
101201201200003 has 2 divisors, whose sum is σ = 101201201200004. Its totient is φ = 101201201200002.
The previous prime is 101201201199983. The next prime is 101201201200079. The reversal of 101201201200003 is 300002102102101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101201201200003 - 229 = 101200664329091 is a prime.
It is not a weakly prime, because it can be changed into another prime (101201301200003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600600600001 + 50600600600002.
It is an arithmetic number, because the mean of its divisors is an integer number (50600600600002).
Almost surely, 2101201201200003 is an apocalyptic number.
101201201200003 is a deficient number, since it is larger than the sum of its proper divisors (1).
101201201200003 is an equidigital number, since it uses as much as digits as its factorization.
101201201200003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 101201201200003 its reverse (300002102102101), we get a palindrome (401203303302104).
The spelling of 101201201200003 in words is "one hundred one trillion, two hundred one billion, two hundred one million, two hundred thousand, three".
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