Base | Representation |
---|---|
bin | 10111000000101010111110… |
… | …001011011111000001011011 |
3 | 111021022202000100001121011122 |
4 | 113000222332023133001123 |
5 | 101231040034242010133 |
6 | 555123105532115455 |
7 | 30213355220462021 |
oct | 2700527613370133 |
9 | 437282010047148 |
10 | 101201210110043 |
11 | 2a27821288490a |
12 | b425580605b8b |
13 | 4461305354aa4 |
14 | 1adc243d3c711 |
15 | ba7720841498 |
hex | 5c0abe2df05b |
101201210110043 has 2 divisors, whose sum is σ = 101201210110044. Its totient is φ = 101201210110042.
The previous prime is 101201210109983. The next prime is 101201210110153. The reversal of 101201210110043 is 340011012102101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101201210110043 - 222 = 101201205915739 is a prime.
It is a super-3 number, since 3×1012012101100433 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (101201210110843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600605055021 + 50600605055022.
It is an arithmetic number, because the mean of its divisors is an integer number (50600605055022).
Almost surely, 2101201210110043 is an apocalyptic number.
101201210110043 is a deficient number, since it is larger than the sum of its proper divisors (1).
101201210110043 is an equidigital number, since it uses as much as digits as its factorization.
101201210110043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 101201210110043 its reverse (340011012102101), we get a palindrome (441212222212144).
The spelling of 101201210110043 in words is "one hundred one trillion, two hundred one billion, two hundred ten million, one hundred ten thousand, forty-three".
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