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101201220211 = 7131112101321
BaseRepresentation
bin101111001000000010…
…0000001001001110011
3100200012212221122121011
41132100010001021303
53124230003021321
6114254033211351
710211601115150
oct1362004011163
9320185848534
10101201220211
1139a124a5683
1217744100b57
13970a640430
144c807cb227
152974916ae1
hex1790101273

101201220211 has 8 divisors (see below), whose sum is σ = 124555348064. Its totient is φ = 80071295040.

The previous prime is 101201220203. The next prime is 101201220251. The reversal of 101201220211 is 112022102101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 101201220211 - 23 = 101201220203 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (13).

It is a junction number, because it is equal to n+sod(n) for n = 101201220191 and 101201220200.

It is not an unprimeable number, because it can be changed into a prime (101201220251) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 556050570 + ... + 556050751.

It is an arithmetic number, because the mean of its divisors is an integer number (15569418508).

Almost surely, 2101201220211 is an apocalyptic number.

101201220211 is a deficient number, since it is larger than the sum of its proper divisors (23354127853).

101201220211 is a wasteful number, since it uses less digits than its factorization.

101201220211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1112101341.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 101201220211 its reverse (112022102101), we get a palindrome (213223322312).

The spelling of 101201220211 in words is "one hundred one billion, two hundred one million, two hundred twenty thousand, two hundred eleven".

Divisors: 1 7 13 91 1112101321 7784709247 14457317173 101201220211