Base | Representation |
---|---|
bin | 10010110110011010… |
… | …01101001110110001 |
3 | 222010021210112022222 |
4 | 21123031031032301 |
5 | 131211222421223 |
6 | 4352113210425 |
7 | 505533425456 |
oct | 113315151661 |
9 | 28107715288 |
10 | 10120123313 |
11 | 4323600483 |
12 | 1b65260a15 |
13 | c53858561 |
14 | 6c00b182d |
15 | 3e36da0c8 |
hex | 25b34d3b1 |
10120123313 has 2 divisors, whose sum is σ = 10120123314. Its totient is φ = 10120123312.
The previous prime is 10120123291. The next prime is 10120123373. The reversal of 10120123313 is 31332102101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8569575184 + 1550548129 = 92572^2 + 39377^2 .
It is a cyclic number.
It is not a de Polignac number, because 10120123313 - 220 = 10119074737 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10120123291 and 10120123300.
It is not a weakly prime, because it can be changed into another prime (10120123373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060061656 + 5060061657.
It is an arithmetic number, because the mean of its divisors is an integer number (5060061657).
Almost surely, 210120123313 is an apocalyptic number.
It is an amenable number.
10120123313 is a deficient number, since it is larger than the sum of its proper divisors (1).
10120123313 is an equidigital number, since it uses as much as digits as its factorization.
10120123313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 10120123313 its reverse (31332102101), we get a palindrome (41452225414).
The spelling of 10120123313 in words is "ten billion, one hundred twenty million, one hundred twenty-three thousand, three hundred thirteen".
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