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1012012413 = 3477177393
BaseRepresentation
bin111100010100100…
…001010101111101
32121112021120001020
4330110201111331
54033033344123
6244230534353
734035651336
oct7424412575
92545246036
101012012413
1147a2889a5
12242b073b9
13131884a19
149859728d
155dca57e3
hex3c52157d

1012012413 has 8 divisors (see below), whose sum is σ = 1378059648. Its totient is φ = 660320064.

The previous prime is 1012012381. The next prime is 1012012429. The reversal of 1012012413 is 3142102101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1012012413 - 25 = 1012012381 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1012012392 and 1012012401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1012012483) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3588556 + ... + 3588837.

It is an arithmetic number, because the mean of its divisors is an integer number (172257456).

Almost surely, 21012012413 is an apocalyptic number.

It is an amenable number.

1012012413 is a deficient number, since it is larger than the sum of its proper divisors (366047235).

1012012413 is an equidigital number, since it uses as much as digits as its factorization.

1012012413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7177443.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 1012012413 is about 31812.1425402314. The cubic root of 1012012413 is about 1003.9882106968.

Adding to 1012012413 its reverse (3142102101), we get a palindrome (4154114514).

The spelling of 1012012413 in words is "one billion, twelve million, twelve thousand, four hundred thirteen".

Divisors: 1 3 47 141 7177393 21532179 337337471 1012012413