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10120127 = 71142537
BaseRepresentation
bin100110100110…
…101110111111
3201001011012112
4212212232333
510042321002
61000524235
7152006513
oct46465677
921034175
1010120127
115792446
12348067b
132134454
1414b6143
15d4d852
hex9a6bbf

10120127 has 4 divisors (see below), whose sum is σ = 10262736. Its totient is φ = 9977520.

The previous prime is 10120111. The next prime is 10120139. The reversal of 10120127 is 72102101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 72102101 = 531360417.

It is a cyclic number.

It is not a de Polignac number, because 10120127 - 24 = 10120111 is a prime.

It is a super-2 number, since 2×101201272 = 204833940992258, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10120147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71198 + ... + 71339.

It is an arithmetic number, because the mean of its divisors is an integer number (2565684).

Almost surely, 210120127 is an apocalyptic number.

10120127 is a deficient number, since it is larger than the sum of its proper divisors (142609).

10120127 is an equidigital number, since it uses as much as digits as its factorization.

10120127 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 142608.

The product of its (nonzero) digits is 28, while the sum is 14.

The square root of 10120127 is about 3181.2147051087. The cubic root of 10120127 is about 216.3027233982.

Adding to 10120127 its reverse (72102101), we get a palindrome (82222228).

The spelling of 10120127 in words is "ten million, one hundred twenty thousand, one hundred twenty-seven".

Divisors: 1 71 142537 10120127