Base | Representation |
---|---|
bin | 10111000000101011001001… |
… | …100111101001111001100011 |
3 | 111021022202111201012212001211 |
4 | 113000223021213221321203 |
5 | 101231040432410402003 |
6 | 555123140550010551 |
7 | 30213363041053162 |
oct | 2700531147517143 |
9 | 437282451185054 |
10 | 101201402044003 |
11 | 2a278301158718 |
12 | b425614946a57 |
13 | 4461336046891 |
14 | 1adc2616213d9 |
15 | ba773260596d |
hex | 5c0ac99e9e63 |
101201402044003 has 2 divisors, whose sum is σ = 101201402044004. Its totient is φ = 101201402044002.
The previous prime is 101201402043947. The next prime is 101201402044037. The reversal of 101201402044003 is 300440204102101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101201402044003 is a prime.
It is not a weakly prime, because it can be changed into another prime (101201402444003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50600701022001 + 50600701022002.
It is an arithmetic number, because the mean of its divisors is an integer number (50600701022002).
Almost surely, 2101201402044003 is an apocalyptic number.
101201402044003 is a deficient number, since it is larger than the sum of its proper divisors (1).
101201402044003 is an equidigital number, since it uses as much as digits as its factorization.
101201402044003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 22.
Adding to 101201402044003 its reverse (300440204102101), we get a palindrome (401641606146104).
The spelling of 101201402044003 in words is "one hundred one trillion, two hundred one billion, four hundred two million, forty-four thousand, three".
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