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101202001022131 is a prime number
BaseRepresentation
bin10111000000101011101101…
…010100100100110010110011
3111021022211001110022002120221
4113000223231110210302303
5101231043144230202011
6555123320224113511
730213413633225122
oct2700535524446263
9437284043262527
10101202001022131
112a278589278869
12b425761465897
1344614001752c9
141adc2badbdab9
15ba7769ec0971
hex5c0aed524cb3

101202001022131 has 2 divisors, whose sum is σ = 101202001022132. Its totient is φ = 101202001022130.

The previous prime is 101202001022093. The next prime is 101202001022159. The reversal of 101202001022131 is 131220100202101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101202001022131 is a prime.

It is a super-4 number, since 4×1012020010221314 (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (101202001022231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50601000511065 + 50601000511066.

It is an arithmetic number, because the mean of its divisors is an integer number (50601000511066).

Almost surely, 2101202001022131 is an apocalyptic number.

101202001022131 is a deficient number, since it is larger than the sum of its proper divisors (1).

101202001022131 is an equidigital number, since it uses as much as digits as its factorization.

101202001022131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 101202001022131 its reverse (131220100202101), we get a palindrome (232422101224232).

The spelling of 101202001022131 in words is "one hundred one trillion, two hundred two billion, one million, twenty-two thousand, one hundred thirty-one".