Base | Representation |
---|---|
bin | 10111000000101011101110… |
… | …011101011000111010110011 |
3 | 111021022211002210012212020011 |
4 | 113000223232131120322303 |
5 | 101231043214122010003 |
6 | 555123322145155351 |
7 | 30213414254404651 |
oct | 2700535635307263 |
9 | 437284083185204 |
10 | 101202020110003 |
11 | 2a27859902586a |
12 | b42576792bb57 |
13 | 44614040c94c7 |
14 | 1adc2bd74bdd1 |
15 | ba776b9e146d |
hex | 5c0aee758eb3 |
101202020110003 has 2 divisors, whose sum is σ = 101202020110004. Its totient is φ = 101202020110002.
The previous prime is 101202020109943. The next prime is 101202020110057. The reversal of 101202020110003 is 300011020202101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101202020110003 - 217 = 101202019978931 is a prime.
It is not a weakly prime, because it can be changed into another prime (101202020110073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50601010055001 + 50601010055002.
It is an arithmetic number, because the mean of its divisors is an integer number (50601010055002).
Almost surely, 2101202020110003 is an apocalyptic number.
101202020110003 is a deficient number, since it is larger than the sum of its proper divisors (1).
101202020110003 is an equidigital number, since it uses as much as digits as its factorization.
101202020110003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 101202020110003 its reverse (300011020202101), we get a palindrome (401213040312104).
The spelling of 101202020110003 in words is "one hundred one trillion, two hundred two billion, twenty million, one hundred ten thousand, three".
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