10120210120117 has 2 divisors, whose sum is σ = 10120210120118. Its totient is φ = 10120210120116.

The previous prime is 10120210120049. The next prime is 10120210120159. The reversal of 10120210120117 is 71102101202101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7361242611921 + 2758967508196 = 2713161^2 + 1661014^2 .

It is an emirp because it is prime and its reverse (71102101202101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10120210120117 - 2¹⁵ = 10120210087349 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10120210120094 and 10120210120103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10120210120217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060105060058 + 5060105060059.

It is an arithmetic number, because the mean of its divisors is an integer number (5060105060059).

Almost surely, 2^{10120210120117} is an apocalyptic number.

It is an amenable number.

10120210120117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10120210120117 is an equidigital number, since it uses as much as digits as its factorization.

10120210120117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 10120210120117 its reverse (71102101202101), we get a palindrome (81222311322218).

The spelling of 10120210120117 in words is "ten trillion, one hundred twenty billion, two hundred ten million, one hundred twenty thousand, one hundred seventeen".