10120210312213 has 4 divisors (see below), whose sum is σ = 10355564040448. Its totient is φ = 9884856583980.

The previous prime is 10120210312211. The next prime is 10120210312243. The reversal of 10120210312213 is 31221301202101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10120210312213 - 2¹ = 10120210312211 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10120210312211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 117676864053 + ... + 117676864138.

It is an arithmetic number, because the mean of its divisors is an integer number (2588891010112).

Almost surely, 2^{10120210312213} is an apocalyptic number.

It is an amenable number.

10120210312213 is a deficient number, since it is larger than the sum of its proper divisors (235353728235).

10120210312213 is an equidigital number, since it uses as much as digits as its factorization.

10120210312213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 235353728234.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10120210312213 its reverse (31221301202101), we get a palindrome (41341511514314).

The spelling of 10120210312213 in words is "ten trillion, one hundred twenty billion, two hundred ten million, three hundred twelve thousand, two hundred thirteen".