101202113 has 4 divisors (see below), whose sum is σ = 106528560. Its totient is φ = 95875668.

The previous prime is 101202107. The next prime is 101202119. The reversal of 101202113 is 311202101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311202101 = 7 ⋅44457443.

It is an interprime number because it is at equal distance from previous prime (101202107) and next prime (101202119).

It is a cyclic number.

It is not a de Polignac number, because 101202113 - 2⁴ = 101202097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101202094 and 101202103.

It is not an unprimeable number, because it can be changed into a prime (101202119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2663195 + ... + 2663232.

It is an arithmetic number, because the mean of its divisors is an integer number (26632140).

Almost surely, 2^101202113 is an apocalyptic number.

It is an amenable number.

101202113 is a deficient number, since it is larger than the sum of its proper divisors (5326447).

101202113 is an equidigital number, since it uses as much as digits as its factorization.

101202113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5326446.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 101202113 is about 10059.9260931679. The cubic root of 101202113 is about 466.0113847784.

Subtracting from 101202113 its product of nonzero digits (12), we obtain a palindrome (101202101).

Adding to 101202113 its reverse (311202101), we get a palindrome (412404214).

The spelling of 101202113 in words is "one hundred one million, two hundred two thousand, one hundred thirteen".