10120211323 has 4 divisors (see below), whose sum is σ = 10120412680. Its totient is φ = 10120009968.

The previous prime is 10120211291. The next prime is 10120211329. The reversal of 10120211323 is 32311202101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32311202101 = 7817 ⋅4133453.

It is a cyclic number.

It is not a de Polignac number, because 10120211323 - 2⁵ = 10120211291 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10120211297 and 10120211306.

It is not an unprimeable number, because it can be changed into a prime (10120211329) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44368 + ... + 149026.

It is an arithmetic number, because the mean of its divisors is an integer number (2530103170).

Almost surely, 2^10120211323 is an apocalyptic number.

10120211323 is a deficient number, since it is larger than the sum of its proper divisors (201357).

10120211323 is an equidigital number, since it uses as much as digits as its factorization.

10120211323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 201356.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 10120211323 its reverse (32311202101), we get a palindrome (42431413424).

The spelling of 10120211323 in words is "ten billion, one hundred twenty million, two hundred eleven thousand, three hundred twenty-three".