Base | Representation |
---|---|
bin | 11101011101000010011… |
… | …01101000101110010011 |
3 | 10120202012112222100222111 |
4 | 32232201031220232103 |
5 | 113040110114133021 |
6 | 2052525544050151 |
7 | 133054564146661 |
oct | 16564115505623 |
9 | 3522175870874 |
10 | 1012022021011 |
11 | 360218058251 |
12 | 144178163957 |
13 | 74582b70641 |
14 | 36da6d57c31 |
15 | 1b4d1dd68e1 |
hex | eba1368b93 |
1012022021011 has 2 divisors, whose sum is σ = 1012022021012. Its totient is φ = 1012022021010.
The previous prime is 1012022020963. The next prime is 1012022021027. The reversal of 1012022021011 is 1101202202101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1012022021011 - 225 = 1011988466579 is a prime.
It is a super-3 number, since 3×10120220210113 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 1012022020982 and 1012022021000.
It is not a weakly prime, because it can be changed into another prime (1012022021611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506011010505 + 506011010506.
It is an arithmetic number, because the mean of its divisors is an integer number (506011010506).
Almost surely, 21012022021011 is an apocalyptic number.
1012022021011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012022021011 is an equidigital number, since it uses as much as digits as its factorization.
1012022021011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 1012022021011 its reverse (1101202202101), we get a palindrome (2113224223112).
The spelling of 1012022021011 in words is "one trillion, twelve billion, twenty-two million, twenty-one thousand, eleven".
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