Base | Representation |
---|---|
bin | 10111000000101011111001… |
… | …111001110001110001100111 |
3 | 111021022211121011111000200002 |
4 | 113000223321321301301213 |
5 | 101231044112244214343 |
6 | 555123353204211515 |
7 | 30213422105325062 |
oct | 2700537171616147 |
9 | 437284534430602 |
10 | 101202212101223 |
11 | 2a2786874386a2 |
12 | b425800099b9b |
13 | 4461434b0b38c |
14 | 1adc2db0478d9 |
15 | ba777d7b78b8 |
hex | 5c0af9e71c67 |
101202212101223 has 2 divisors, whose sum is σ = 101202212101224. Its totient is φ = 101202212101222.
The previous prime is 101202212101129. The next prime is 101202212101253. The reversal of 101202212101223 is 322101212202101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101202212101223 - 28 = 101202212100967 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101202212101195 and 101202212101204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101202212101253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50601106050611 + 50601106050612.
It is an arithmetic number, because the mean of its divisors is an integer number (50601106050612).
Almost surely, 2101202212101223 is an apocalyptic number.
101202212101223 is a deficient number, since it is larger than the sum of its proper divisors (1).
101202212101223 is an equidigital number, since it uses as much as digits as its factorization.
101202212101223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 101202212101223 its reverse (322101212202101), we get a palindrome (423303424303324).
The spelling of 101202212101223 in words is "one hundred one trillion, two hundred two billion, two hundred twelve million, one hundred one thousand, two hundred twenty-three".
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