Base | Representation |
---|---|
bin | 10010110110011011… |
… | …00101110101110001 |
3 | 222010021222122121022 |
4 | 21123031211311301 |
5 | 131211234132423 |
6 | 4352115305225 |
7 | 505534325366 |
oct | 113315456561 |
9 | 28107878538 |
10 | 10120224113 |
11 | 432366a18a |
12 | 1b652ab215 |
13 | c538923bc |
14 | 6c00da46d |
15 | 3e3709dc8 |
hex | 25b365d71 |
10120224113 has 8 divisors (see below), whose sum is σ = 10316926368. Its totient is φ = 9925302304.
The previous prime is 10120224067. The next prime is 10120224143. The reversal of 10120224113 is 31142202101.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10120224113 - 212 = 10120220017 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 10120224091 and 10120224100.
It is not an unprimeable number, because it can be changed into a prime (10120224143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 433631 + ... + 456372.
It is an arithmetic number, because the mean of its divisors is an integer number (1289615796).
Almost surely, 210120224113 is an apocalyptic number.
It is an amenable number.
10120224113 is a deficient number, since it is larger than the sum of its proper divisors (196702255).
10120224113 is an equidigital number, since it uses as much as digits as its factorization.
10120224113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 890223.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 10120224113 its reverse (31142202101), we get a palindrome (41262426214).
The spelling of 10120224113 in words is "ten billion, one hundred twenty million, two hundred twenty-four thousand, one hundred thirteen".
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