Base | Representation |
---|---|
bin | 10010110110011011… |
… | …11011010100110001 |
3 | 222010022011010022120 |
4 | 21123031323110301 |
5 | 131211244441423 |
6 | 4352121224453 |
7 | 505535143062 |
oct | 113315732461 |
9 | 28108133276 |
10 | 10120312113 |
11 | 432371a30a |
12 | 1b65332129 |
13 | c538c3482 |
14 | 6c0120569 |
15 | 3e3725ee3 |
hex | 25b37b531 |
10120312113 has 8 divisors (see below), whose sum is σ = 13858445568. Its totient is φ = 6564526704.
The previous prime is 10120312073. The next prime is 10120312117. The reversal of 10120312113 is 31121302101.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 10120312113 - 212 = 10120308017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10120312092 and 10120312101.
It is not an unprimeable number, because it can be changed into a prime (10120312117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45586881 + ... + 45587102.
It is an arithmetic number, because the mean of its divisors is an integer number (1732305696).
Almost surely, 210120312113 is an apocalyptic number.
It is an amenable number.
10120312113 is a deficient number, since it is larger than the sum of its proper divisors (3738133455).
10120312113 is an equidigital number, since it uses as much as digits as its factorization.
10120312113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 91174023.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 10120312113 its reverse (31121302101), we get a palindrome (41241614214).
The spelling of 10120312113 in words is "ten billion, one hundred twenty million, three hundred twelve thousand, one hundred thirteen".
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