10120323113 has 4 divisors (see below), whose sum is σ = 10214905680. Its totient is φ = 10025740548.

The previous prime is 10120323107. The next prime is 10120323151. The reversal of 10120323113 is 31132302101.

10120323113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10120323113 - 2¹² = 10120319017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10120323091 and 10120323100.

It is not an unprimeable number, because it can be changed into a prime (10120323163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47291123 + ... + 47291336.

It is an arithmetic number, because the mean of its divisors is an integer number (2553726420).

Almost surely, 2^10120323113 is an apocalyptic number.

It is an amenable number.

10120323113 is a deficient number, since it is larger than the sum of its proper divisors (94582567).

10120323113 is an equidigital number, since it uses as much as digits as its factorization.

10120323113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94582566.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 10120323113 its reverse (31132302101), we get a palindrome (41252625214).

The spelling of 10120323113 in words is "ten billion, one hundred twenty million, three hundred twenty-three thousand, one hundred thirteen".