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10120331433 = 311093041879
BaseRepresentation
bin10010110110011100…
…00000000010101001
3222010022012002211010
421123032000002221
5131211301101213
64352121454133
7505535253312
oct113316000251
928108162733
1010120331433
114323732883
121b65341349
13c538cc1c4
146c0127609
153e372bac3
hex25b3800a9

10120331433 has 8 divisors (see below), whose sum is σ = 13505947200. Its totient is φ = 6740801648.

The previous prime is 10120331413. The next prime is 10120331461. The reversal of 10120331433 is 33413302101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10120331433 - 29 = 10120330921 is a prime.

It is a super-2 number, since 2×101203314332 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (10120331413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1517613 + ... + 1524266.

It is an arithmetic number, because the mean of its divisors is an integer number (1688243400).

Almost surely, 210120331433 is an apocalyptic number.

It is an amenable number.

10120331433 is a deficient number, since it is larger than the sum of its proper divisors (3385615767).

10120331433 is a wasteful number, since it uses less digits than its factorization.

10120331433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3042991.

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 10120331433 its reverse (33413302101), we get a palindrome (43533633534).

The spelling of 10120331433 in words is "ten billion, one hundred twenty million, three hundred thirty-one thousand, four hundred thirty-three".

Divisors: 1 3 1109 3327 3041879 9125637 3373443811 10120331433