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10121013313 is a prime number
BaseRepresentation
bin10010110110100001…
…00110100001000001
3222010100110202011221
421123100212201001
5131211434411223
64352144235041
7505544123305
oct113320464101
928110422157
1010121013313
114324059114
121b6560ba81
13c53aaa698
146c0263d05
153e3813b5d
hex25b426841

10121013313 has 2 divisors, whose sum is σ = 10121013314. Its totient is φ = 10121013312.

The previous prime is 10121013299. The next prime is 10121013319. The reversal of 10121013313 is 31331012101.

10121013313 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10049661504 + 71351809 = 100248^2 + 8447^2 .

It is a cyclic number.

It is not a de Polignac number, because 10121013313 - 29 = 10121012801 is a prime.

It is not a weakly prime, because it can be changed into another prime (10121013319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060506656 + 5060506657.

It is an arithmetic number, because the mean of its divisors is an integer number (5060506657).

Almost surely, 210121013313 is an apocalyptic number.

It is an amenable number.

10121013313 is a deficient number, since it is larger than the sum of its proper divisors (1).

10121013313 is an equidigital number, since it uses as much as digits as its factorization.

10121013313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 10121013313 its reverse (31331012101), we get a palindrome (41452025414).

The spelling of 10121013313 in words is "ten billion, one hundred twenty-one million, thirteen thousand, three hundred thirteen".