Base | Representation |
---|---|
bin | 11101011101001011111… |
… | …11100100110100011011 |
3 | 10120202102010212221210112 |
4 | 32232211333210310123 |
5 | 113040241132033313 |
6 | 2052541531034535 |
7 | 133056556635302 |
oct | 16564577446433 |
9 | 3522363787715 |
10 | 1012102221083 |
11 | 3602593557a8 |
12 | 14419ab9ba4b |
13 | 74596670ac5 |
14 | 36db3873439 |
15 | 1b4d8e798a8 |
hex | eba5fe4d1b |
1012102221083 has 2 divisors, whose sum is σ = 1012102221084. Its totient is φ = 1012102221082.
The previous prime is 1012102221079. The next prime is 1012102221113. The reversal of 1012102221083 is 3801222012101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1012102221083 - 22 = 1012102221079 is a prime.
It is a super-2 number, since 2×10121022210832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1012102121083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506051110541 + 506051110542.
It is an arithmetic number, because the mean of its divisors is an integer number (506051110542).
Almost surely, 21012102221083 is an apocalyptic number.
1012102221083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012102221083 is an equidigital number, since it uses as much as digits as its factorization.
1012102221083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 1012102221083 its reverse (3801222012101), we get a palindrome (4813324233184).
The spelling of 1012102221083 in words is "one trillion, twelve billion, one hundred two million, two hundred twenty-one thousand, eighty-three".
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