1012103113 has 4 divisors (see below), whose sum is σ = 1156689280. Its totient is φ = 867516948.

The previous prime is 1012103101. The next prime is 1012103119. The reversal of 1012103113 is 3113012101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3113012101 = 26017 ⋅119653.

It is a cyclic number.

It is not a de Polignac number, because 1012103113 - 2¹⁷ = 1011972041 is a prime.

It is a super-2 number, since 2×1012103113² = 2048705422688581538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1012103093 and 1012103102.

It is not an unprimeable number, because it can be changed into a prime (1012103119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72293073 + ... + 72293086.

It is an arithmetic number, because the mean of its divisors is an integer number (289172320).

Almost surely, 2^1012103113 is an apocalyptic number.

It is an amenable number.

1012103113 is a deficient number, since it is larger than the sum of its proper divisors (144586167).

1012103113 is an equidigital number, since it uses as much as digits as its factorization.

1012103113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 144586166.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 1012103113 is about 31813.5680645853. The cubic root of 1012103113 is about 1004.0182034154.

Adding to 1012103113 its reverse (3113012101), we get a palindrome (4125115214).

The spelling of 1012103113 in words is "one billion, twelve million, one hundred three thousand, one hundred thirteen".