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101211040121 is a prime number
BaseRepresentation
bin101111001000010100…
…1011110100101111001
3100200020120102112222112
41132100221132211321
53124240011240441
6114255023502105
710212050434502
oct1362051364571
9320216375875
10101211040121
1139a17aa2504
1217747457935
13970c69b029
144c81c25ba9
1529757064eb
hex1790a5e979

101211040121 has 2 divisors, whose sum is σ = 101211040122. Its totient is φ = 101211040120.

The previous prime is 101211040109. The next prime is 101211040123. The reversal of 101211040121 is 121040112101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101210514496 + 525625 = 318136^2 + 725^2 .

It is a cyclic number.

It is not a de Polignac number, because 101211040121 - 214 = 101211023737 is a prime.

Together with 101211040123, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 101211040096 and 101211040105.

It is not a weakly prime, because it can be changed into another prime (101211040123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50605520060 + 50605520061.

It is an arithmetic number, because the mean of its divisors is an integer number (50605520061).

Almost surely, 2101211040121 is an apocalyptic number.

It is an amenable number.

101211040121 is a deficient number, since it is larger than the sum of its proper divisors (1).

101211040121 is an equidigital number, since it uses as much as digits as its factorization.

101211040121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 101211040121 its reverse (121040112101), we get a palindrome (222251152222).

The spelling of 101211040121 in words is "one hundred one billion, two hundred eleven million, forty thousand, one hundred twenty-one".