101211101113 has 2 divisors, whose sum is σ = 101211101114. Its totient is φ = 101211101112.

The previous prime is 101211101107. The next prime is 101211101129. The reversal of 101211101113 is 311101112101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 87431393344 + 13779707769 = 295688^2 + 117387^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101211101113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101211101093 and 101211101102.

It is not a weakly prime, because it can be changed into another prime (101211101153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50605550556 + 50605550557.

It is an arithmetic number, because the mean of its divisors is an integer number (50605550557).

Almost surely, 2^101211101113 is an apocalyptic number.

It is an amenable number.

101211101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101211101113 is an equidigital number, since it uses as much as digits as its factorization.

101211101113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 101211101113 its reverse (311101112101), we get a palindrome (412312213214).

The spelling of 101211101113 in words is "one hundred one billion, two hundred eleven million, one hundred one thousand, one hundred thirteen".