Base | Representation |
---|---|
bin | 11101011101001101001… |
… | …01010011101000000011 |
3 | 10120202102211111110202122 |
4 | 32232212211103220003 |
5 | 113040301200042011 |
6 | 2052542523034455 |
7 | 133060040002211 |
oct | 16564645235003 |
9 | 3522384443678 |
10 | 1012112112131 |
11 | 3602639a101a |
12 | 1441a236ba2b |
13 | 74598724bb3 |
14 | 36db4cc9cb1 |
15 | 1b4d9c803db |
hex | eba6953a03 |
1012112112131 has 2 divisors, whose sum is σ = 1012112112132. Its totient is φ = 1012112112130.
The previous prime is 1012112112091. The next prime is 1012112112157. The reversal of 1012112112131 is 1312112112101.
1012112112131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1012112112131 - 226 = 1012045003267 is a prime.
It is a super-2 number, since 2×10121121121312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1012112112181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506056056065 + 506056056066.
It is an arithmetic number, because the mean of its divisors is an integer number (506056056066).
Almost surely, 21012112112131 is an apocalyptic number.
1012112112131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012112112131 is an equidigital number, since it uses as much as digits as its factorization.
1012112112131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 17.
Adding to 1012112112131 its reverse (1312112112101), we get a palindrome (2324224224232).
The spelling of 1012112112131 in words is "one trillion, twelve billion, one hundred twelve million, one hundred twelve thousand, one hundred thirty-one".
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