Base | Representation |
---|---|
bin | 11101011101001101001… |
… | …01101100000000001111 |
3 | 10120202102211200112201212 |
4 | 32232212211230000033 |
5 | 113040301211240413 |
6 | 2052542525125035 |
7 | 133060040566265 |
oct | 16564645540017 |
9 | 3522384615655 |
10 | 1012112211983 |
11 | 360263a5a044 |
12 | 1441a23b977b |
13 | 7459875b492 |
14 | 36db4d14435 |
15 | 1b4d9c9eca8 |
hex | eba696c00f |
1012112211983 has 2 divisors, whose sum is σ = 1012112211984. Its totient is φ = 1012112211982.
The previous prime is 1012112211949. The next prime is 1012112212061. The reversal of 1012112211983 is 3891122112101.
1012112211983 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1012112211983 - 220 = 1012111163407 is a prime.
It is a super-2 number, since 2×10121122119832 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1012112214983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506056105991 + 506056105992.
It is an arithmetic number, because the mean of its divisors is an integer number (506056105992).
Almost surely, 21012112211983 is an apocalyptic number.
1012112211983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012112211983 is an equidigital number, since it uses as much as digits as its factorization.
1012112211983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 32.
The spelling of 1012112211983 in words is "one trillion, twelve billion, one hundred twelve million, two hundred eleven thousand, nine hundred eighty-three".
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