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101211320131 is a prime number
BaseRepresentation
bin101111001000010101…
…0100010111101000011
3100200020120221210002021
41132100222202331003
53124240044221011
6114255033502311
710212053012035
oct1362052427503
9320216853067
10101211320131
1139a18173919
1217747571997
13970c76860c
144c81c99c55
15297575e471
hex1790aa2f43

101211320131 has 2 divisors, whose sum is σ = 101211320132. Its totient is φ = 101211320130.

The previous prime is 101211320113. The next prime is 101211320143. The reversal of 101211320131 is 131023112101.

It is a happy number.

Together with previous prime (101211320113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101211320131 - 25 = 101211320099 is a prime.

It is a super-2 number, since 2×1012113201312 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (101211321131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50605660065 + 50605660066.

It is an arithmetic number, because the mean of its divisors is an integer number (50605660066).

Almost surely, 2101211320131 is an apocalyptic number.

101211320131 is a deficient number, since it is larger than the sum of its proper divisors (1).

101211320131 is an equidigital number, since it uses as much as digits as its factorization.

101211320131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 101211320131 its reverse (131023112101), we get a palindrome (232234432232).

The spelling of 101211320131 in words is "one hundred one billion, two hundred eleven million, three hundred twenty thousand, one hundred thirty-one".