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1012121001113 is a prime number
BaseRepresentation
bin11101011101001110001…
…11001101110010011001
310120202110110020002011012
432232213013031302121
5113040310434013423
62052543441343305
7133060205363465
oct16564707156231
93522413202135
101012121001113
11360268a12492
121441a5337b35
137459a517b51
1436db61614a5
151b4da939078
hexeba71cdc99

1012121001113 has 2 divisors, whose sum is σ = 1012121001114. Its totient is φ = 1012121001112.

The previous prime is 1012121001077. The next prime is 1012121001119. The reversal of 1012121001113 is 3111001212101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 984960972304 + 27160028809 = 992452^2 + 164803^2 .

It is a cyclic number.

It is not a de Polignac number, because 1012121001113 - 222 = 1012116806809 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1012121001119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506060500556 + 506060500557.

It is an arithmetic number, because the mean of its divisors is an integer number (506060500557).

Almost surely, 21012121001113 is an apocalyptic number.

It is an amenable number.

1012121001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012121001113 is an equidigital number, since it uses as much as digits as its factorization.

1012121001113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 1012121001113 its reverse (3111001212101), we get a palindrome (4123122213214).

The spelling of 1012121001113 in words is "one trillion, twelve billion, one hundred twenty-one million, one thousand, one hundred thirteen".