Search a number
-
+
10121314213 is a prime number
BaseRepresentation
bin10010110110100011…
…01111111110100101
3222010101001000221101
421123101233332211
5131212024023323
64352154520101
7505546515463
oct113321577645
928111030841
1010121314213
11432424419a
121b65736031
13c53b8462a
146c0301833
153e3872dad
hex25b46ffa5

10121314213 has 2 divisors, whose sum is σ = 10121314214. Its totient is φ = 10121314212.

The previous prime is 10121314199. The next prime is 10121314219. The reversal of 10121314213 is 31241312101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6143110884 + 3978203329 = 78378^2 + 63073^2 .

It is an emirp because it is prime and its reverse (31241312101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10121314213 - 217 = 10121183141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10121314219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060657106 + 5060657107.

It is an arithmetic number, because the mean of its divisors is an integer number (5060657107).

Almost surely, 210121314213 is an apocalyptic number.

It is an amenable number.

10121314213 is a deficient number, since it is larger than the sum of its proper divisors (1).

10121314213 is an equidigital number, since it uses as much as digits as its factorization.

10121314213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 10121314213 its reverse (31241312101), we get a palindrome (41362626314).

The spelling of 10121314213 in words is "ten billion, one hundred twenty-one million, three hundred fourteen thousand, two hundred thirteen".