Base | Representation |
---|---|
bin | 101111001000100110… |
… | …0011011001100010001 |
3 | 100200021012122222122222 |
4 | 1132101030123030101 |
5 | 3124244332414413 |
6 | 114255552110425 |
7 | 10212221341334 |
oct | 1362114331421 |
9 | 320235588588 |
10 | 101220201233 |
11 | 39a2218a378 |
12 | 1774a535415 |
13 | 9711557ac8 |
14 | 4c8312c61b |
15 | 2976415b08 |
hex | 179131b311 |
101220201233 has 2 divisors, whose sum is σ = 101220201234. Its totient is φ = 101220201232.
The previous prime is 101220201179. The next prime is 101220201283. The reversal of 101220201233 is 332102022101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 89142850624 + 12077350609 = 298568^2 + 109897^2 .
It is a cyclic number.
It is not a de Polignac number, because 101220201233 - 218 = 101219939089 is a prime.
It is not a weakly prime, because it can be changed into another prime (101220201283) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50610100616 + 50610100617.
It is an arithmetic number, because the mean of its divisors is an integer number (50610100617).
Almost surely, 2101220201233 is an apocalyptic number.
It is an amenable number.
101220201233 is a deficient number, since it is larger than the sum of its proper divisors (1).
101220201233 is an equidigital number, since it uses as much as digits as its factorization.
101220201233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 101220201233 its reverse (332102022101), we get a palindrome (433322223334).
The spelling of 101220201233 in words is "one hundred one billion, two hundred twenty million, two hundred one thousand, two hundred thirty-three".
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