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101220201331 = 107123944897
BaseRepresentation
bin101111001000100110…
…0011011001101110011
3100200021012122222210121
41132101030123031303
53124244332420311
6114255552111111
710212221341534
oct1362114331563
9320235588717
10101220201331
1139a2218a457
121774a535497
139711557b72
144c8312c68b
152976415b71
hex179131b373

101220201331 has 4 divisors (see below), whose sum is σ = 101221253352. Its totient is φ = 101219149312.

The previous prime is 101220201319. The next prime is 101220201367. The reversal of 101220201331 is 133102022101.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 101220201331 - 29 = 101220200819 is a prime.

It is a super-2 number, since 2×1012202013312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101220201371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 365326 + ... + 579571.

It is an arithmetic number, because the mean of its divisors is an integer number (25305313338).

Almost surely, 2101220201331 is an apocalyptic number.

101220201331 is a deficient number, since it is larger than the sum of its proper divisors (1052021).

101220201331 is an equidigital number, since it uses as much as digits as its factorization.

101220201331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1052020.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 101220201331 its reverse (133102022101), we get a palindrome (234322223432).

The spelling of 101220201331 in words is "one hundred one billion, two hundred twenty million, two hundred one thousand, three hundred thirty-one".

Divisors: 1 107123 944897 101220201331