101220222113 has 2 divisors, whose sum is σ = 101220222114. Its totient is φ = 101220222112.

The previous prime is 101220222091. The next prime is 101220222133. The reversal of 101220222113 is 311222022101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96877807504 + 4342414609 = 311252^2 + 65897^2 .

It is an emirp because it is prime and its reverse (311222022101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101220222113 - 2¹⁶ = 101220156577 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101220222091 and 101220222100.

It is not a weakly prime, because it can be changed into another prime (101220222133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50610111056 + 50610111057.

It is an arithmetic number, because the mean of its divisors is an integer number (50610111057).

Almost surely, 2^101220222113 is an apocalyptic number.

It is an amenable number.

101220222113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101220222113 is an equidigital number, since it uses as much as digits as its factorization.

101220222113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 101220222113 its reverse (311222022101), we get a palindrome (412442244214).

The spelling of 101220222113 in words is "one hundred one billion, two hundred twenty million, two hundred twenty-two thousand, one hundred thirteen".