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1012204314197 is a prime number
BaseRepresentation
bin11101011101011000001…
…01000001111001010101
310120202200020222211012222
432232230011001321111
5113040443301023242
62053000015152125
7133062236465666
oct16565405017125
93522606884188
101012204314197
11360300a4687a
12144209215645
13745b186822b
1436dc324b36d
151b4e2de45d2
hexebac141e55

1012204314197 has 2 divisors, whose sum is σ = 1012204314198. Its totient is φ = 1012204314196.

The previous prime is 1012204314169. The next prime is 1012204314241. The reversal of 1012204314197 is 7914134022101.

1012204314197 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 908207094001 + 103997220196 = 952999^2 + 322486^2 .

It is a cyclic number.

It is not a de Polignac number, because 1012204314197 - 26 = 1012204314133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1012204314127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506102157098 + 506102157099.

It is an arithmetic number, because the mean of its divisors is an integer number (506102157099).

Almost surely, 21012204314197 is an apocalyptic number.

It is an amenable number.

1012204314197 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012204314197 is an equidigital number, since it uses as much as digits as its factorization.

1012204314197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 35.

Adding to 1012204314197 its reverse (7914134022101), we get a palindrome (8926338336298).

The spelling of 1012204314197 in words is "one trillion, twelve billion, two hundred four million, three hundred fourteen thousand, one hundred ninety-seven".