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101221100083 is a prime number
BaseRepresentation
bin101111001000100111…
…1110110101000110011
3100200021021100122122201
41132101033312220303
53124300100200313
6114300023244031
710212232104025
oct1362117665063
9320237318581
10101221100083
1139a22743724
121774a8a9617
1397117b0c7c
144c832c4015
1529765420dd
hex17913f6a33

101221100083 has 2 divisors, whose sum is σ = 101221100084. Its totient is φ = 101221100082.

The previous prime is 101221100077. The next prime is 101221100093. The reversal of 101221100083 is 380001122101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 101221100083 - 25 = 101221100051 is a prime.

It is a super-2 number, since 2×1012211000832 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 101221100083.

It is not a weakly prime, because it can be changed into another prime (101221100093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50610550041 + 50610550042.

It is an arithmetic number, because the mean of its divisors is an integer number (50610550042).

Almost surely, 2101221100083 is an apocalyptic number.

101221100083 is a deficient number, since it is larger than the sum of its proper divisors (1).

101221100083 is an equidigital number, since it uses as much as digits as its factorization.

101221100083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 101221100083 its reverse (380001122101), we get a palindrome (481222222184).

The spelling of 101221100083 in words is "one hundred one billion, two hundred twenty-one million, one hundred thousand, eighty-three".