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10122211993 is a prime number
BaseRepresentation
bin10010110110101010…
…01011001010011001
3222010102201122110111
421123111023022121
5131212241240433
64352230044321
7505560245065
oct113325131231
928112648414
1010122211993
1143247a7763
121b65aa96a1
13c5410a16a
146c0496aa5
153e399ddcd
hex25b54b299

10122211993 has 2 divisors, whose sum is σ = 10122211994. Its totient is φ = 10122211992.

The previous prime is 10122211969. The next prime is 10122211999. The reversal of 10122211993 is 39911222101.

10122211993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5957832969 + 4164379024 = 77187^2 + 64532^2 .

It is an emirp because it is prime and its reverse (39911222101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10122211993 - 225 = 10088657561 is a prime.

It is not a weakly prime, because it can be changed into another prime (10122211999) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5061105996 + 5061105997.

It is an arithmetic number, because the mean of its divisors is an integer number (5061105997).

Almost surely, 210122211993 is an apocalyptic number.

It is an amenable number.

10122211993 is a deficient number, since it is larger than the sum of its proper divisors (1).

10122211993 is an equidigital number, since it uses as much as digits as its factorization.

10122211993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 31.

The spelling of 10122211993 in words is "ten billion, one hundred twenty-two million, two hundred eleven thousand, nine hundred ninety-three".