Search a number
-
+
10122222113 is a prime number
BaseRepresentation
bin10010110110101010…
…01101101000100001
3222010102202011100022
421123111031220201
5131212242101423
64352230203225
7505560316433
oct113325155041
928112664308
1010122222113
114324804323
121b65ab3515
13c54111953
146c049a653
153e39a1dc8
hex25b54da21

10122222113 has 2 divisors, whose sum is σ = 10122222114. Its totient is φ = 10122222112.

The previous prime is 10122222073. The next prime is 10122222179. The reversal of 10122222113 is 31122222101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9660530944 + 461691169 = 98288^2 + 21487^2 .

It is a cyclic number.

It is not a de Polignac number, because 10122222113 - 210 = 10122221089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10122222091 and 10122222100.

It is not a weakly prime, because it can be changed into another prime (10122222193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5061111056 + 5061111057.

It is an arithmetic number, because the mean of its divisors is an integer number (5061111057).

Almost surely, 210122222113 is an apocalyptic number.

It is an amenable number.

10122222113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10122222113 is an equidigital number, since it uses as much as digits as its factorization.

10122222113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 10122222113 its reverse (31122222101), we get a palindrome (41244444214).

The spelling of 10122222113 in words is "ten billion, one hundred twenty-two million, two hundred twenty-two thousand, one hundred thirteen".